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[Pixelschmied]

Hello WMs,

I have a door in my scene and if you "LeftClick" the actor "WalkTo" to this door and speaks a sentence. The same with "LeftDoubleClick" and "RunTo" with the same sentence. All works fine, but I have a question: It is possible that I set only once this sentence, because I do not want to do everything twice, because it's the same thing. I hope you can understand what I mean.

My door script look like this:

Code: WME Script

1. on "LeftClick"
2. {
3.         actor.WalkTo(220, 621);
4.         actor.TurnTo(DI_UP);
5.         actor.Talk("This door is closed!");
6. }
7.  
8. on "LeftDoubleClick"
9. {
10.         actor.RunTo(220, 621);
11.         actor.TurnTo(DI_UP);
12.         actor.Talk("This door is closed");
13. }
14.  

My idea was e.g.

var = WasClicked = 0;
and within on "LeftClick" and "LeftDoubleClick" I set the WasClicked +1
and after all I will ask if(WasClicked == 1)
{
actor.Talk("This door is closed!")
}

I don't know how I should do it. Thank you in advance for your help.

[metamorphium]

first of all, you'd need a global variable for this. I'd do this code like this:

Code: [Select]

#include "base.inc"

global doorTested;

function handleDoor()  // I hate triplicating code, let's keep it tidy
{
       actor.TurnTo(DI_UP);
       if (!doorTested) actor.Talk("This door is closed!");
       doorTested = true;
}

on "LeftClick"
{
    actor.WalkTo(220, 621);
        handleDoor(); 
}

on "LeftDoubleClick"
{
actor.RunTo(220, 621);
        handleDoor(); 
}



[Pixelschmied]

Thank you very much for your help metamorphium. It works all fine and will continue to try to learn.

[Pixelschmied]

Hallo WMs,

I play around with this code-snippets above and I noticed - I hope I declare right-  that the function is not always invited. It sometimes works only one time, on another twice or it makes no problem. Confusing or? Perhaps I have too much coffee drunk .

I change into the function handleDoor() the global variable doorTested from = true to false, tested araound and now it is working always.

All have a good night,

Pixelschmied

[metamorphium]

problem might be if you click "out of the action". Which means that the variable is not set and you can get this behavior. You can fix this by this:

Code: [Select]


function handleDoor() 
{
       actor.TurnTo(DI_UP);

       if (!doorTested)
       {
          doorTested = true;
          actor.Talk("This door is closed!");
       }
}


Now when actor talks, you're sure he won't be talking again, as the variable has been set already.

[Pixelschmied]

Hello metamorphium,

thank you for your fast response. I think that I understand it. When the actor talk only once then the variable "doorTested" is set to true, and thus is the condition met. If I want the character always talk his sentence when "LeftClick" or "LeftDoubleClick" the e.g. door, I can make it as above because the variable is set to false and therefore the value is not set.

Is the way right? If so, then I see light at the end of the dungeon

Nice day,
Pixelschmied

[metamorphium]

yes, but if you want him always to say the line, you don't need this variable at all. 

[Pixelschmied]

Hello metamorphium,

ah ok, because the value of the variable will not changed. I see even a more little light shines on  Thanks a lot for your help and quick-teaching.

With bravest coding greets,

Pixelschmied